회사에서 DB의 컬럼값에 대한 유사성을 대조하는 로직을 찾던 중..

http://stackoverflow.com/questions/8518695/t-sql-get-percentage-of-character-match-of-2-strings

위의 로직을 발견..

상당히 괜찮다!!

SELECT  [dbo].[GetPercentageOfTwoStringMatching]('valentin123456'  ,'valnetin123456')

CREATE FUNCTION [dbo].[GetPercentageOfTwoStringMatching]
(
    @string1 NVARCHAR(100)
    ,@string2 NVARCHAR(100)
)
RETURNS INT
AS
BEGIN

    DECLARE @levenShteinNumber INT

    DECLARE @string1Length INT = LEN(@string1)
    , @string2Length INT = LEN(@string2)
    DECLARE @maxLengthNumber INT = CASE WHEN @string1Length > @string2Length THEN @string1Length ELSE @string2Length END

    SELECT @levenShteinNumber = [dbo].[LEVENSHTEIN] (   @string1  ,@string2)

    DECLARE @percentageOfBadCharacters INT = @levenShteinNumber * 100 / @maxLengthNumber

    DECLARE @percentageOfGoodCharacters INT = 100 - @percentageOfBadCharacters

    -- Return the result of the function
    RETURN @percentageOfGoodCharacters

END




-- =============================================     
-- Create date: 2011.12.14
-- Description: http://blog.sendreallybigfiles.com/2009/06/improved-t-sql-levenshtein-distance.html
-- =============================================

CREATE FUNCTION [dbo].[LEVENSHTEIN](@left  VARCHAR(100),
                                    @right VARCHAR(100))
returns INT
AS
  BEGIN
      DECLARE @difference    INT,
              @lenRight      INT,
              @lenLeft       INT,
              @leftIndex     INT,
              @rightIndex    INT,
              @left_char     CHAR(1),
              @right_char    CHAR(1),
              @compareLength INT

      SET @lenLeft = LEN(@left)
      SET @lenRight = LEN(@right)
      SET @difference = 0

      IF @lenLeft = 0
        BEGIN
            SET @difference = @lenRight

            GOTO done
        END

      IF @lenRight = 0
        BEGIN
            SET @difference = @lenLeft

            GOTO done
        END

      GOTO comparison

      COMPARISON:

      IF ( @lenLeft >= @lenRight )
        SET @compareLength = @lenLeft
      ELSE
        SET @compareLength = @lenRight

      SET @rightIndex = 1
      SET @leftIndex = 1

      WHILE @leftIndex <= @compareLength
        BEGIN
            SET @left_char = substring(@left, @leftIndex, 1)
            SET @right_char = substring(@right, @rightIndex, 1)

            IF @left_char <> @right_char
              BEGIN -- Would an insertion make them re-align?
                  IF( @left_char = substring(@right, @rightIndex + 1, 1) )
                    SET @rightIndex = @rightIndex + 1
                  -- Would an deletion make them re-align?
                  ELSE IF( substring(@left, @leftIndex + 1, 1) = @right_char )
                    SET @leftIndex = @leftIndex + 1

                  SET @difference = @difference + 1
              END

            SET @leftIndex = @leftIndex + 1
            SET @rightIndex = @rightIndex + 1
        END

      GOTO done

      DONE:

      RETURN @difference
  END 

MySQL에서 jdbc 연결 시 Unknown DataBase 'SID이름' 오류 발생

분명 맞는 코드를 사용했다고 생각하고 java 프로그램을 작성했는데..

DB에 테스트 연결을 할때.. 계속해서

Unknown DataBase ~~~ 오류 발생

이래저래 찾아보니.. 여러가지 이유가 나오나. 보통은 접속 정보가 잘못됨 이라는 내용들..

다시한번 코드를 잘 보니까.. Connection String에 끝에 세미콜론이 들어가서 발생한 문제...

private static String url = "jdbc:mysql://192.168.0.56:3306/glpi;";

이 코드를

private static String url = "jdbc:mysql://192.168.0.56:3306/glpi";

로 수정하니까 말끔히 해결..

지나친 Ctrl + C + V 는 오류를 동반합니다.. ㅡㅡ;;;